Hello, smplease!
Did you make a sketch?
Find the domain and range of: .$\displaystyle f(x) = 22+x$
We have: .$\displaystyle f(x) \:=\:2x2$
You should know the graph of: .$\displaystyle f(x) \:=\:x$
. . It is a $\displaystyle \vee$ with its vertex at the origin.
The graph of: .$\displaystyle f(x) \:=\:x2$ .is the previous graph moved 2 units to the right.
The graph of: .$\displaystyle f(x) \:=\:2x2$ .is the previous graph
. . reflected over the $\displaystyle x$axis and is "steeper".
Hence, the graph of $\displaystyle f(x) \:=\:2x2$ looks like this: Code:

 2
   +  *    
 / \
 / \
/ \
/ \
/ \

Got it?