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- Mar 16th 2010, 12:48 AM #1

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## Log Help

Seems to be a lot of log help going on tonight.. here's one that im not sure where to start..

also,

Now on this on i figured out that i need to convert to exponential form this gives me:

then i multiply out:

rearrange:

now i figure punch it into the quadratic formula and call it a day? the program i'm putting it into for HW says it's only 1/2 right if i put in and yes i tried since it is +/-... ideas?

oh and by the way, how do i put square root symbols in these messages?

- Mar 16th 2010, 01:41 AM #2

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- Mar 16th 2010, 04:17 AM #3

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[QUOTE=xsavethesporksx;475365]Seems to be a lot of log help going on tonight.. here's one that im not sure where to start..

Take the logarithm (either "common" or "natural"- whichever is simpler on your calculator) of both sides to get (6x-3)log(6)= (4x- 6)log(5) so that 6log(6)x- 3log(6)= 4log(5)x- 6log(5). Solve that linear equation for x. That is the same as saying as Wilmer gives.

also,

Now on this on i figured out that i need to convert to exponential form this gives me:

then i multiply out:

rearrange:

now i figure punch it into the quadratic formula and call it a day? the program i'm putting it into for HW says it's only 1/2 right if i put in and yes i tried since it is +/-... ideas?

oh and by the way, how do i put square root symbols in these messages?**without**the spaces inside [ ] gives .

Clicking on any such formula will show you the code to produce it. There is a tutorial here:

http://www.mathhelpforum.com/math-help/latex-help/