Seems to be a lot of log help going on tonight.. here's one that im not sure where to start..

also,

Now on this on i figured out that i need to convert to exponential form this gives me:

$\displaystyle 4^4=x^2/(x+5)$

then i multiply out:

$\displaystyle 256x+1280=x^2$

rearrange:

$\displaystyle x^2-256x-1280=0$

now i figure punch it into the quadratic formula and call it a day? the program i'm putting it into for HW says it's only 1/2 right if i put in $\displaystyle (256+sqrt(70656))/2 $ and yes i tried $\displaystyle (256-sqrt(70656))/2 $ since it is +/-... ideas?

oh and by the way, how do i put square root symbols in these messages?