I have no idea. Can you show me the answer step by step, please.

The Arrhenius equation is given by

k = A exp (-E/RT),

where k is the rate constant, A is called the pre-exponential factor, E is called the activation energy, R is the ideal gas constant and T is the temperature , measured in Kelvins.

By taking logs and simplifying show that this equation can be written in the form
1n k = m/T + n,

identifying the value of the parameters m and n.

2. Originally Posted by AJShaw
I have no idea. Can you show me the answer step by step, please.

The Arrhenius equation is given by

k = A exp (-E/RT),

where k is the rate constant, A is called the pre-exponential factor, E is called the activation energy, R is the ideal gas constant and T is the temperature , measured in Kelvins.

By taking logs and simplifying show that this equation can be written in the form
1n k = m/T + n,

identifying the value of the parameters m and n.

$\displaystyle \ln(Ae^{-E\slash RT}) = \ln A - \frac{E}{RT}$

Tonio

3. Could you elaborate more, please. I really don't get it.

4. k = A exp (-E/RT),
ln(k) = ln(A) + (-E/R)*1/T
Now can you find the values of m and n?