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Math Help - Maths in action - hard question, please help

  1. #1
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    Maths in action - hard question, please help

    I have no idea. Can you show me the answer step by step, please.


    The Arrhenius equation is given by

    k = A exp (-E/RT),

    where k is the rate constant, A is called the pre-exponential factor, E is called the activation energy, R is the ideal gas constant and T is the temperature , measured in Kelvins.

    By taking logs and simplifying show that this equation can be written in the form
    1n k = m/T + n,

    identifying the value of the parameters m and n.
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  2. #2
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    Quote Originally Posted by AJShaw View Post
    I have no idea. Can you show me the answer step by step, please.


    The Arrhenius equation is given by

    k = A exp (-E/RT),

    where k is the rate constant, A is called the pre-exponential factor, E is called the activation energy, R is the ideal gas constant and T is the temperature , measured in Kelvins.

    By taking logs and simplifying show that this equation can be written in the form
    1n k = m/T + n,

    identifying the value of the parameters m and n.

    \ln(Ae^{-E\slash RT}) = \ln A - \frac{E}{RT}

    Tonio
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  3. #3
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    Could you elaborate more, please. I really don't get it.
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  4. #4
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    k = A exp (-E/RT),
    ln(k) = ln(A) + (-E/R)*1/T
    Now can you find the values of m and n?
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