5x^4-4x^3+19x^2-16x-4
I divided it by x^4+4
= 5x^2-4x-1
I always having hard time factoring.... can you factor me this quadratic equation please.... 5x^2-4x-1 thanks...
Dear Anemori,
If you factorize, $\displaystyle 5x^2-4x-1=(5x+1)(x-1)$
Anyway your division is wrong. You would not get $\displaystyle 5x^2-4x-1$ when $\displaystyle 5x^4-4x^3+19x^2-16x-4 $ is divided by, $\displaystyle x^4+4$. Quite obvious since if you multiply $\displaystyle x^4+4$ and $\displaystyle 5x^2-4x-1$ you would get a 6th degree polynomial.
Hope this will help you.
Dear Anemori,
Also I want to share this factorizing calculator which you would find handy to check your calculations.
Algebra.Help -- Factoring Calculator