Hey Math Helpers Having some trouble with simplifying this one. $\displaystyle \frac{3+x}{x} - \frac{x^2+2}{x^2}$ Do I square both sides? Cheers
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Originally Posted by stabza Hey Math Helpers Having some trouble with simplifying this one. $\displaystyle \frac{3+x}{x} - \frac{x^2+2}{x^2}$ Do I square both sides? Cheers get a common denominator and combine the fractions into a single fraction.
$\displaystyle \frac {x^2(3+x)}{x^3} - \frac{x(x^2+2)}{x^3} $ = $\displaystyle \frac{3x^2+x^3-x^3+2x}{x^3}$ Is this next stop wrong? = $\displaystyle \frac {3x - 2}{x^2}$ Thanks
Originally Posted by stabza $\displaystyle \frac {x^2(3+x)}{x^3} - \frac{x(x^2+2)}{x^3} $ = $\displaystyle \frac{3x^2+x^3-x^3+2x}{x^3}$ Is this next stop wrong? = $\displaystyle \frac {3x - 2}{x^2}$ Thanks Actually, your final answer is right but you failed on the signs in the middle step : $\displaystyle \frac {x^2(3+x)}{x^3} - \frac{x(x^2+2)}{x^3}$ $\displaystyle \frac{3x^2+x^3-x^3 {\color{red}{-}} 2x}{x^3}$ $\displaystyle \frac {3x - 2}{x^2}$
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