The period of vibration, P, for a pendulum varies directly as the square root of the length L. If P is 2 seconds when L is 64 inches, what is the period when the length is 16 inches?
The period of vibration, P, for a pendulum varies directly as the square root of the length L. If P is 2 seconds when L is 64 inches, what is the period when the length is 16 inches?
$\displaystyle P = k\sqrt{L}$ , where $\displaystyle k$ is the constant of proportionality.
$\displaystyle 2 = k\sqrt{64}$
solve for $\displaystyle k$ , then determine $\displaystyle P$ for $\displaystyle L = 16$