1. ## Solving for x

If x varies inversely as v and x=6 when v=3, then find x when v=9.

2. Originally Posted by Mike9182
If x varies inversely as v and x=6 when v=3, then find x when v=9.
$x = \frac{k}{v}$

$x_1 = \frac{k}{v_1}$

$x_2 = \frac{k}{v_2}$

Where $x_1 = 6$, $v_1 = 3$, $v_2=9$

$\frac{x_2}{x_1} = \frac{\frac{k}{v_2}}{\frac{k}{v_1}} = \frac{v_1}{v_2}$

Solve: $x_2 = \frac{x_1 v_1}{v_2}$