0 = PR^n - Q(R^n)-1)/R-1 It needs to equal P. It's part of a modeling and problem solving question, I'm right with everything after the rearranging. Thank you.
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Originally Posted by Liparulo 0 = PR^n - Q(R^n)-1)/R-1 It needs to equal P. It's part of a modeling and problem solving question, I'm right with everything after the rearranging. Thank you. Do you mean: $\displaystyle 0=\dfrac{PR^n-Q(R^n)-1}{R-1}$ or: $\displaystyle 0=\dfrac{PR^n-QR^{n-1}}{R-1}$ or: $\displaystyle 0=PR^n - \dfrac{QR^n-1}{R-1}$ or: $\displaystyle 0=PR^n - \dfrac{QR^{n-1}}{R-1}$
Originally Posted by earboth or: $\displaystyle 0=PR^n - \dfrac{QR^n-1}{R-1}$ This one. Sorry, I know it's a basic question and I should be able to do it, but I'm just not clicking at the moment.
Originally Posted by Liparulo This one. Sorry, I know it's a basic question and I should be able to do it, but I'm just not clicking at the moment. 1. Move the quotient to the other side of the equation: $\displaystyle PR^n = \dfrac{QR^n-1}{R-1}$ and then divide by $\displaystyle R^n$ $\displaystyle P = \dfrac{QR^n-1}{R^n(R-1)} $
Thank you very much. I knew it was simple algebra that was holding me back.
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