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Math Help - Solving quadratic word problems - Help

  1. #1
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    Solving quadratic word problems - Help

    Area of a Rectangle P=2l+2w
    x=width,1.6x=the length of the rectangle
    2(1.6x)+2x=9000m^2
    3.2x+2x=9000m^2
    5.2x=9000m^2
    5.2x/5.2=(9000m^2)/5.2

    I am not sure what to do at this point. Any suggestions?
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  2. #2
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    Quote Originally Posted by mcruz65 View Post
    Area of a Rectangle P=2l+2w
    x=width,1.6x=the length of the rectangle
    2(1.6x)+2x=9000m^2
    3.2x+2x=9000m^2
    5.2x=9000m^2
    5.2x/5.2=(9000m^2)/5.2

    I am not sure what to do at this point. Any suggestions?
    ... area of a rectangle is A = LW

    P = 2L + 2W is the perimeter.
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  3. #3
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    Solving quadratic word problems - Help

    Here is the actual problem. Golden Rectangle. The so-called golden rectangle is said to be extremely pleasing visually and was used often by ancient Greek and Roman architects. The length of a golden rectangle is approximately 1.6 times the width. Find the dimensions of a golden rectangle if its area is 9000 m^2.

    w = the width of the rectangle and 1.6w = the length

    Area = length x width

    w x 1.6w = 9000 m^2

    1.6w^2 = 9000 m^2

    sqrt(1.6w^2) = sqrt(9000 m^2)

    1.6w = 9000m

    1.6w/1.6 = 9000m/1.6

    w = 5625

    Is this correct??
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  4. #4
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    Quote Originally Posted by mcruz65 View Post
    Here is the actual problem. Golden Rectangle. The so-called golden rectangle is said to be extremely pleasing visually and was used often by ancient Greek and Roman architects. The length of a golden rectangle is approximately 1.6 times the width. Find the dimensions of a golden rectangle if its area is 9000 m^2.

    w = the width of the rectangle and 1.6w = the length

    Area = length x width

    w x 1.6w = 9000 m^2

    1.6w^2 = 9000 m^2

    sqrt(1.6w^2) = sqrt(9000 m^2)

    1.6w = 9000m

    1.6w/1.6 = 9000m/1.6

    w = 5625

    Is this correct??

    1.6w^2 = 9000

    w^2 = \frac{9000}{1.6}

    w = \sqrt{\frac{9000}{1.6}}
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