Area of a Rectangle P=2l+2w
x=width,1.6x=the length of the rectangle
2(1.6x)+2x=9000m^2
3.2x+2x=9000m^2
5.2x=9000m^2
5.2x/5.2=(9000m^2)/5.2
I am not sure what to do at this point. Any suggestions?
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Area of a Rectangle P=2l+2w
x=width,1.6x=the length of the rectangle
2(1.6x)+2x=9000m^2
3.2x+2x=9000m^2
5.2x=9000m^2
5.2x/5.2=(9000m^2)/5.2
I am not sure what to do at this point. Any suggestions?
... area of a rectangle is A = LWQuote:
Originally Posted by mcruz65
P = 2L + 2W is the perimeter.
Here is the actual problem. Golden Rectangle. The so-called golden rectangle is said to be extremely pleasing visually and was used often by ancient Greek and Roman architects. The length of a golden rectangle is approximately 1.6 times the width. Find the dimensions of a golden rectangle if its area is 9000 m^2.
w = the width of the rectangle and 1.6w = the length
Area = length x width
w x 1.6w = 9000 m^2
1.6w^2 = 9000 m^2
sqrt(1.6w^2) = sqrt(9000 m^2)
1.6w = 9000m
1.6w/1.6 = 9000m/1.6
w = 5625
Is this correct??
Quote:
Originally Posted by mcruz65