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**Mukilab** On a desert island, five men and a monkey gather coconuts all day, then sleep.

The first man awakens and decides to take his share. He divides the coconuts into five equal shares with one left over. He gives the extra one the, hides his share and goes back to sleep. Later the second man awakens and takes his fifth from the remaining pike; he too finds one extra one and gives it to the monkey. Each of the remaining three men does likewise in turn. Find the minimum number of coconuts originally present.

I need a full explanation + answer please.

I tried starting off with $\displaystyle \frac{x}{5} \cdot \frac{5}{1}$

Would I do this but adding 1 each time?