Can anyone factor this please. i'm bad on factoring polynomials.
6x^3+17x^2+x-10
thanks...
Positive integers are unhelpful here, but if
hence is a solution, so is a factor.
a=6, c=-10
Hence, a+b=17, b=17-a=17-6=11
or b+c=1, b-10=1, b=10+1=11
Using this technique, "a" and "c" are found immediately,
"b" can be found from either of the other two co-efficients using "a" or "c".
The quadratic is easier to factorise.
We get