Positive integers are unhelpful here, but if

hence is a solution, so is a factor.

a=6, c=-10

Hence, a+b=17, b=17-a=17-6=11

or b+c=1, b-10=1, b=10+1=11

Using this technique, "a" and "c" are found immediately,

"b" can be found from either of the other two co-efficients using "a" or "c".

The quadratic is easier to factorise.

We get