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Math Help - graphing question connected with wolfram alpha

  1. #1
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    graphing question connected with wolfram alpha

    hi, when i'm doing linear equations, i often check them on wolfram alpha. when i enter 2x+3y=6 it shows the line on the graph, solves for y BUT also lists the INTEGER SOLUTION. in this example it's

    x=3n , y=-2(n-1)

    how are these equations derived? thanks, any help appreciated
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  2. #2
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    Quote Originally Posted by damon View Post
    hi, when i'm doing linear equations, i often check them on wolfram alpha. when i enter 2x+3y=6 it shows the line on the graph, solves for y BUT also lists the INTEGER SOLUTION. in this example it's

    x=3n , y=-2(n-1)

    how are these equations derived? thanks, any help appreciated
    Because 3 and 6 are both divisible by 3 so must x be. Put x=3n for some n \in \mathbb{Z}, then:

    y=2(1-n)

    which is also in \mathbb{Z} and you are done.

    CB
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