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Thread: graphing question connected with wolfram alpha

  1. #1
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    graphing question connected with wolfram alpha

    hi, when i'm doing linear equations, i often check them on wolfram alpha. when i enter 2x+3y=6 it shows the line on the graph, solves for y BUT also lists the INTEGER SOLUTION. in this example it's

    x=3n , y=-2(n-1)

    how are these equations derived? thanks, any help appreciated
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  2. #2
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    Quote Originally Posted by damon View Post
    hi, when i'm doing linear equations, i often check them on wolfram alpha. when i enter 2x+3y=6 it shows the line on the graph, solves for y BUT also lists the INTEGER SOLUTION. in this example it's

    x=3n , y=-2(n-1)

    how are these equations derived? thanks, any help appreciated
    Because $\displaystyle 3$ and $\displaystyle 6$ are both divisible by $\displaystyle 3$ so must $\displaystyle x$ be. Put $\displaystyle x=3n$ for some $\displaystyle n \in \mathbb{Z}$, then:

    $\displaystyle y=2(1-n)$

    which is also in $\displaystyle \mathbb{Z}$ and you are done.

    CB
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