Ok here some excercise from the book that I don't get it because the book the does not have an example how to do this.
f(x)= .5x^2-.5
I couldn't figure out how to transform this to standard form of quadratic function from general form.
please anyone can explain how.... thanks!
That should have been obvious immediately.
Since a square is never negative, is never negative so is ".5 plus something". That is, y is never less than .5 and will be equal to .5 only when x= 0. The vertex, the lowest point on the graph, is at (0, .5).
(Don't just memorize formulas. Think about what you are doing!)