a) (x+1/y)^2
b) (x-(1/3y)+(2/5z))^2
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a) (x+1/y)^2
b) (x-(1/3y)+(2/5z))^2
Hi Prove it,
It's the second combination.
So for the first one would it be x^2 + (1/y)x + (1/y)x + (1/y)^2 or is it x^2 + (1/xy) + (1/xy) + (1/y)^2
???
Cool, so my final answer for the first one is x^2 + (2x/y) + (1/y)^2
Am I right?
a) (x+1/y)^2
(x+1/y)^2 = (x+1/y)(x+1/y)
(x+1/y)(x+1/y)= x^2+x/y+x/y+1/y
x^2+x/y+x/y+1/y= x^2+2x/y+1/y
Answer= x^2+2x/y+1/y
and it was right
No it wasn't.
Reread my post, you'll notice something you missed.