a) (x+1/y)^2

b) (x-(1/3y)+(2/5z))^2

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- Mar 9th 2010, 09:11 PMbrumby_3Expand and simplify
**a) (x+1/y)^2**

b) (x-(1/3y)+(2/5z))^2 - Mar 9th 2010, 09:19 PMProve It
$\displaystyle \left(x + \frac{1}{y}\right)^2 = \left(x + \frac{1}{y}\right)\left(x + \frac{1}{y}\right)$.

FOIL it out.

I can't read the second. Has it got $\displaystyle \frac{1}{3y}$ and $\displaystyle \frac{2}{5z}$, or $\displaystyle \frac{1}{3}y$ and $\displaystyle \frac{2}{5}z$? - Mar 9th 2010, 09:27 PMbrumby_3
Hi Prove it,

It's the second combination.

So for the first one would it be x^2 + (1/y)x + (1/y)x + (1/y)^2 or is it x^2 + (1/xy) + (1/xy) + (1/y)^2

??? - Mar 9th 2010, 09:37 PMProve It
- Mar 9th 2010, 09:39 PMbrumby_3
Cool, so my final answer for the first one is x^2 + (2x/y) + (1/y)^2

Am I right? - Mar 9th 2010, 09:57 PMProve It
- Mar 10th 2010, 09:29 AMArcane10Solution
**a) (x+1/y)^2**

**(x+1/y)^2 = (x+1/y)****(x+1/y)**

**(x+1/y)****(x+1/y)= x^2+x/y+x/y+1/y**

**x^2+x/y+x/y+1/y**= x^2+2x/y+1/y

Answer= x^2+2x/y+1/y - Mar 10th 2010, 04:59 PMProve It
- Mar 12th 2010, 08:05 AMArcane10
and it was right

- Mar 12th 2010, 04:18 PMProve It
No it wasn't.

Reread my post, you'll notice something you missed.