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Math Help - Prove the pythagorean theorem

  1. #1
    Senior Member Mukilab's Avatar
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    Prove the pythagorean theorem

    Prove that a^2+b^2=c^2 using:
    a=m^2-n^2
    b=2mn
    c=m^2+n^2

    So far I have got:
    (m*m)(m*m)-(n*n)(n*n)+4(m*m)(n*n)=(m*m)(m*m)-(n*n)(n*n)

    What can I do with 4(m*m)(n*n)?
    Can I do (m*m)+(m*m)+(m*m)+(m*m)*(n*n)+(n*n)+(n*n)+(n*n)



    ???

    ~Cyf
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  2. #2
    Master Of Puppets
    pickslides's Avatar
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    Quote Originally Posted by Mukilab View Post
    Prove that a^2+b^2=c^2 using:


    a=m^2-n^2
    b=2mn
    c=m^2+n^2
    For this proof to work you must use the LHS to show the RHS

    a^2+b^2

    (m^2-n^2)^2+(2mn)^2

    (m^2-n^2)(m^2-n^2)+4m^2n^2

    m^4-2n^2m^2+n^4+4m^2n^2

    m^4+2n^2m^2+n^4

    Now factor this term and you will get c^2
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