Solve for x:

2(2x – 5) + 1 = x – 8 – 5x

This is a practice problem I am working on, so that when I get to my homework, I have some sense in what I am doing...Thanks

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- Apr 3rd 2007, 05:28 AMproudmomof2Need some help solving equation
Solve for x:

2(2x – 5) + 1 = x – 8 – 5x

This is a practice problem I am working on, so that when I get to my homework, I have some sense in what I am doing...Thanks - Apr 3rd 2007, 06:11 AM^_^Engineer_Adam^_^
2(2x – 5) + 1 = x – 8 – 5x

2(2x-5) = -4x - 7 <<<< transfer 1 to the right side

4x - 10 = -4x - 7 <<<< multiply 2(2x-5) = 2(2x) - 2(5) or to distribute

8x = 3 <<< 4x + 4x = -7 + 10

thus,,,

x = 3 / 8 - Apr 3rd 2007, 07:01 AMjagabandhu
Problem

2(2x – 5) + 1 = x – 8 – 5x

Solution:

2(2x-5)+1=x-8-5x

=>4x-10+1=x-8-5x <---- remove the brackets with appropriate operation

=>4x-x+5x=10-1-8 <---- take all the x terms to the left and numbers to the

right

=>8x=1 <---- here you have simplified

=>x=1/8 <---- here you get the result

This is the solution actually.