i understood a,b and c but d made not alot of sense. how do i go backwards? thanks
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still confused.
. So, using what I've said above, to what power must you raise 64 to get 8?
64 ^ .5 = 8 thanks i cant do 64 ^ .5 to get 2 so what do I do?
It's better to think about the exponents as fractions. If Then If Then So it's easiest to work backwards. So
For G, H and I remember that an exponent raised to an exponent is just the two exponents multiplied together. so, x^2^6=x^12
so to get 81 to 3 you do 81^.25 hjowever for 64 -> 2 how do i do 2^1/6 to check?
That's correct!
Originally Posted by Quacky That's correct! awsome, thank you. i know its unrelated, but how do i do these? for a i have .5 = x is that correct? thanks
I would do that by writing both as 5^{something} So So: Part b) is harder. Try to write it out as powers of 3. For part c) Try to write it out as powers of 2
Is this not a logarithm problem? then
Originally Posted by minneola24 awsome, thank you. -snip- i know its unrelated, but how do i do these? for a i have .5 = x is that correct? thanks A is x=2. 125 is 25^2, so 25^3 = 125^2 As for B, I have the answer but I can't explain why it works so I won't post it.
Originally Posted by integral Is this not a logarithm problem? then Don't confuse the OP, integral (even your signature seems to be an extension of your answer xD) For part c), you could note that , and try to find yourself with just two's on the right side. Then note that . The rest should follow.
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