http://img11.imageshack.us/img11/8986/scan0002lq.jpg

i understood a,b and c but d made not alot of sense. how do i go backwards? thanks

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- Mar 8th 2010, 05:31 PMminneola24Backward Exponets
http://img11.imageshack.us/img11/8986/scan0002lq.jpg

i understood a,b and c but d made not alot of sense. how do i go backwards? thanks - Mar 8th 2010, 05:36 PMQuacky
Hint:

- Mar 8th 2010, 05:38 PMminneola24
still confused.

- Mar 8th 2010, 05:39 PMQuacky
.

So, using what I've said above, to what power must you raise 64 to get 8? - Mar 8th 2010, 05:48 PMminneola24
64 ^ .5 = 8

thanks

i cant do 64 ^ .5 to get 2 so what do I do? - Mar 8th 2010, 05:53 PMQuacky
It's better to think about the exponents as fractions.

If

Then

If

Then

So it's easiest to work backwards.

So - Mar 8th 2010, 05:54 PMVertazontal
For G, H and I remember that an exponent raised to an exponent is just the two exponents multiplied together.

so,

x^2^6=x^12 - Mar 8th 2010, 06:07 PMminneola24
so to get 81 to 3 you do 81^.25

hjowever for 64 -> 2 how do i do 2^1/6 to check? - Mar 8th 2010, 06:12 PMQuacky
That's correct! (Happy)

- Mar 8th 2010, 06:15 PMminneola24
awsome, thank you.

http://img197.imageshack.us/img197/2392/scan0002iu.jpg

i know its unrelated, but how do i do these?

for a i have

.5 = x

is that correct? thanks - Mar 8th 2010, 06:24 PMQuacky

I would do that by writing both as 5^{something}

So

So:

Part b) is harder. Try to write it out as powers of 3.

For part c) Try to write it out as powers of 2 - Mar 8th 2010, 06:25 PMintegral
Is this not a logarithm problem?

then

- Mar 8th 2010, 06:27 PMVertazontal
- Mar 8th 2010, 08:21 PMBacterius