Hello, aznmartinjai!

Here's a baby-talk explanation of Jhevon's excellent solution.

Two drovers hired a pasture together for $7.

The first put in 4 oxen and the second, thirty sheep.

What should each pay if one ox eats as much as ten sheep?

The livestock is distributed like this: Code:

*--------------*--------------*
| | |
| 4 oxen | 30 sheep |
| | |
*--------------*--------------*

Since one ox eats eats as much as ten sheep,

. . the distribution is equivalent to: Code:

*--------------*--------------*
| | |
| 40 sheep | 30 sheep |
| | |
*--------------*--------------*

And *that*'s where Jhevon got the 4/7 and 3/7