Two drovers hired a pasture together for $7. The first put in 4 oxen and the second, thirty sheep. What should each pay if one ox eats as much as ten sheep?

Results 1 to 3 of 3

- April 2nd 2007, 09:56 PM #1

- Joined
- Feb 2007
- From
- NEW YORK
- Posts
- 63

- April 2nd 2007, 10:03 PM #2
one ox eats as much as ten sheep, that means four oxen will eat as much as forty sheep.

so the oxen are consuming a ratio 4/7, while the sheep consume 3/7

(okay, so technically this sentence makes no sense, but i think you get what i'm trying to say)

so the owner of the oxen should pay $(4/7)*7 = $4

while the owner of the sheep pays $(3/7)*7 = $3

- April 3rd 2007, 05:07 AM #3

- Joined
- May 2006
- From
- Lexington, MA (USA)
- Posts
- 11,981
- Thanks
- 812

Hello, aznmartinjai!

Here's a baby-talk explanation of Jhevon's excellent solution.

Two drovers hired a pasture together for $7.

The first put in 4 oxen and the second, thirty sheep.

What should each pay if one ox eats as much as ten sheep?

The livestock is distributed like this:Code:*--------------*--------------* | | | | 4 oxen | 30 sheep | | | | *--------------*--------------*

Since one ox eats eats as much as ten sheep,

. . the distribution is equivalent to:Code:*--------------*--------------* | | | | 40 sheep | 30 sheep | | | | *--------------*--------------*

And*that*'s where Jhevon got the 4/7 and 3/7