Two drovers hired a pasture together for $7. The first put in 4 oxen and the second, thirty sheep. What should each pay if one ox eats as much as ten sheep?

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- April 2nd 2007, 10:56 PMaznmartinjaiOx and Sheep
Two drovers hired a pasture together for $7. The first put in 4 oxen and the second, thirty sheep. What should each pay if one ox eats as much as ten sheep?

- April 2nd 2007, 11:03 PMJhevon
one ox eats as much as ten sheep, that means four oxen will eat as much as forty sheep.

so the oxen are consuming a ratio 4/7, while the sheep consume 3/7

(okay, so technically this sentence makes no sense, but i think you get what i'm trying to say)

so the owner of the oxen should pay $(4/7)*7 = $4

while the owner of the sheep pays $(3/7)*7 = $3 - April 3rd 2007, 06:07 AMSoroban
Hello, aznmartinjai!

Here's a baby-talk explanation of Jhevon's excellent solution.

Quote:

Two drovers hired a pasture together for $7.

The first put in 4 oxen and the second, thirty sheep.

What should each pay if one ox eats as much as ten sheep?

The livestock is distributed like this:Code:`*--------------*--------------*`

| | |

| 4 oxen | 30 sheep |

| | |

*--------------*--------------*

Since one ox eats eats as much as ten sheep,

. . the distribution is equivalent to:Code:`*--------------*--------------*`

| | |

| 40 sheep | 30 sheep |

| | |

*--------------*--------------*

And*that*'s where Jhevon got the 4/7 and 3/7