# Math Help - Log question

1. ## Log question

I have been doing some review questions for a course and can't find anything on how to do this, just remember that I need to change it into a log question somehow:

3(5^x)-1 = 2
5^(x)+2

Would appreciate some hints as to how to solve it.

Thanks

2. Originally Posted by daRitz
I have been doing some review questions for a course and can't find anything on how to do this, just remember that I need to change it into a log question somehow:

3(5^x)-1 = 2
5^(x)+2

Would appreciate some hints as to how to solve it.

Thanks
I take it that this is

$\frac{3\left(5^x\right) - 1}{5^x + 2} = 2$

$3\left(5^x\right) - 1 = 2\left(5^x + 2\right)$

$3\left(5^x\right) - 1 = 2\left(5^x\right) + 4$

$5^x = 5$.

What do you think $x$ has to be?

3. Hey, thank you very much. You made it seem so simple!