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Math Help - Log question

  1. #1
    Newbie daRitz's Avatar
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    Log question

    I have been doing some review questions for a course and can't find anything on how to do this, just remember that I need to change it into a log question somehow:

    3(5^x)-1 = 2
    5^(x)+2


    Would appreciate some hints as to how to solve it.

    Thanks
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  2. #2
    MHF Contributor
    Prove It's Avatar
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    Quote Originally Posted by daRitz View Post
    I have been doing some review questions for a course and can't find anything on how to do this, just remember that I need to change it into a log question somehow:

    3(5^x)-1 = 2
    5^(x)+2


    Would appreciate some hints as to how to solve it.

    Thanks
    I take it that this is

    \frac{3\left(5^x\right) - 1}{5^x + 2} = 2

    3\left(5^x\right) - 1 = 2\left(5^x + 2\right)

    3\left(5^x\right) - 1 = 2\left(5^x\right) + 4

    5^x = 5.


    What do you think x has to be?
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  3. #3
    Newbie daRitz's Avatar
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    Apr 2008
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    Hey, thank you very much. You made it seem so simple!
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