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Math Help - factorsing this expression

  1. #1
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    factorsing this expression

    the expression is 6a^2-a-2

    now this is what ive done.......

    taken out the common factor of -ve.
    1. -(6a^2+a+2)

    2. -[(6a^2+a+12)]

    3. -[(6a^2+4a-3a+12)]

    4. -[2a(3a+2)-3(a-4)]
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  2. #2
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    Quote Originally Posted by johnsy123 View Post
    the expression is 6a^2-a-2

    now this is what ive done.......

    taken out the common factor of -ve.
    1. -(6a^2+a+2)

    2. -[(6a^2+a+12)]

    3. -[(6a^2+4a-3a+12)]

    4. -[2a(3a+2)-3(a-4)]
    You don't need to take out a negative common factor, because the first value is already positive...

    You need 2 numbers that multiply to become 6(-2) = -12 and add to become -1.

    The two numbers are -4 and 3.


    6a^2 - a - 2 = 6a^2 - 4a + 3a - 2

     = 2a(3a - 2) + 1(3a - 2)

     = (3a - 2)(2a + 1).
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  3. #3
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    Assuming the equation you have written is correct:

    6a^2 - a - 2

    6a^2 + 3a - 4a - 2

    3a(2a + 1) - 2(2a + 1)

    (3a - 2)(2a + 1)
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