# Solving inequalities

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• December 18th 2011, 12:11 PM
JodieR11
Re: Solving inequalities
Thank you, looks great!
• April 25th 2012, 02:48 AM
hp12345
Re: Solving inequalities
thanks man I was searching for something like this for whole day
• May 8th 2012, 10:49 AM
Keroro
Re: Solving inequalities
can anyone help with this question please:
Use the addition property and/or multiplication properties to find a and b if:
-3<x<4 then a<x-5<b
• May 8th 2012, 10:54 AM
Keroro
Re: Solving inequalities
Use the addition property and/or multiplication properties to find a and b if:
-3<x<4 then a<x-5<b
• August 14th 2012, 01:28 AM
DIOGYK
Re: Solving inequalities
Thank you. This will be very helpful!
• August 19th 2012, 12:29 AM
IceDancer91
Re: Solving inequalities
This is very helpful but i am still stuck on a particular inequality. 2-3x<|x-3|. So far i have used the modular property and obtained a three term quadratic equation which further factorizes to (2x+1)(4x-5)<0. So according to me the answer is -1/2<x<5/4 but according to the marking scheme its only x>-1/2. Can somebody plz explain why?
• December 25th 2012, 07:24 PM
tomjackson
Re: Solving inequalities
I was completely surprised by seeing all these meshes especially the triparts insert mesh.
• March 8th 2013, 09:05 AM
mthCCC2013
Re: Solving inequalities
Greatly appreciated.
• March 15th 2013, 11:47 AM
SVCrankson
Re: Solving inequalities
• May 10th 2013, 07:48 AM
Dacu
Re: Solving inequalities
Hello!
Solve the inequality $3x^2+4ix+5<0$ , where $i^2=-1$.
Thank You!
• June 10th 2013, 04:10 AM
Julian21
Re: Solving inequalities
Thank you so much nice tutorial.
• September 18th 2013, 10:28 AM
Bonganitedd
Re: Solving inequalities
I have trouble solving inequalities especially quadratic. My main problem is presenting critical points. I hope you attachment will solve my problem. Thank you
• September 19th 2013, 04:59 AM
Dacu
Re: Solving inequalities
Quote:

Originally Posted by Bonganitedd
I have trouble solving inequalities especially quadratic. My main problem is presenting critical points. I hope you attachment will solve my problem. Thank you

Any inequality can be written as an equation and so $ax^2+bx+c\leq 0$ you can write the equation as $ax^2+bx+c=d\leq 0$.The solutions of the inequality are :

$x=\frac{-b\pm \sqrt{b^2-4a(c-d)}}{2a}$ where $d\leq 0$.
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