Thank you, looks great!

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- Dec 18th 2011, 12:11 PMJodieR11Re: Solving inequalities
Thank you, looks great!

- Apr 25th 2012, 02:48 AMhp12345Re: Solving inequalities
thanks man I was searching for something like this for whole day

- May 8th 2012, 10:49 AMKeroroRe: Solving inequalities
can anyone help with this question please:

Use the addition property and/or multiplication properties to find a and b if:

-3<x<4 then a<x-5<b - May 8th 2012, 10:54 AMKeroroRe: Solving inequalities
Use the addition property and/or multiplication properties to find a and b if:

-3<x<4 then a<x-5<b - Aug 14th 2012, 01:28 AMDIOGYKRe: Solving inequalities
Thank you. This will be very helpful!

- Aug 19th 2012, 12:29 AMIceDancer91Re: Solving inequalities
This is very helpful but i am still stuck on a particular inequality.

**2-3x<|x-3|**. So far i have used the modular property and obtained a three term quadratic equation which further factorizes to**(2x+1)(4x-5)<0**. So according to me the answer is**-1/2<x<5/4**but according to the marking scheme its only**x>-1/2**. Can somebody plz explain why? - Dec 25th 2012, 07:24 PMtomjacksonRe: Solving inequalities
I was completely surprised by seeing all these meshes especially the triparts insert mesh.

- Mar 8th 2013, 09:05 AMmthCCC2013Re: Solving inequalities
Greatly appreciated.

- Mar 15th 2013, 11:47 AMSVCranksonRe: Solving inequalities
Very helpful

- May 10th 2013, 07:48 AMDacuRe: Solving inequalities
Hello!

Solve the inequality $\displaystyle 3x^2+4ix+5<0$ , where $\displaystyle i^2=-1$.

Thank You! - Jun 10th 2013, 04:10 AMJulian21Re: Solving inequalities
Thank you so much nice tutorial.

- Sep 18th 2013, 10:28 AMBonganiteddRe: Solving inequalities
I have trouble solving inequalities especially quadratic. My main problem is presenting critical points. I hope you attachment will solve my problem. Thank you

- Sep 19th 2013, 04:59 AMDacuRe: Solving inequalities
Any inequality can be written as an equation and so $\displaystyle ax^2+bx+c\leq 0$ you can write the equation as $\displaystyle ax^2+bx+c=d\leq 0$.The solutions of the inequality are :

$\displaystyle x=\frac{-b\pm \sqrt{b^2-4a(c-d)}}{2a}$ where $\displaystyle d\leq 0$.