# Thread: Stuck while solving equation!

1. ## Stuck while solving equation!

I was solving an equation and got to a point where I have no clue what to do next! $\displaystyle 40.96=x^2-20x+y^2-22y+221$ As you can see I have to find x and y, looks simple, but damn I forgot how to solve it! If anyone could help I would appreciate it a lot!

2. Originally Posted by crapmathematician
I was solving an equation and got to a point where I have no clue what to do next! $\displaystyle 40.96=x^2-20x+y^2-22y+221$ As you can see I have to find x and y, looks simple, but damn I forgot how to solve it! If anyone could help I would appreciate it a lot!
you have two unknowns in one equation. You need another equation

bjh

3. Originally Posted by crapmathematician
I was solving an equation and got to a point where I have no clue what to do next! $\displaystyle 40.96=x^2-20x+y^2-22y+221$ As you can see I have to find x and y, looks simple, but damn I forgot how to solve it! If anyone could help I would appreciate it a lot!

4. Originally Posted by bjhopper
you have two unknowns in one equation. You need another equation

bjh
Could you be more precise?

5. Originally Posted by mathemagister
The situation is: There are two points in a coordinate axis X1(10;11) and Xn(X;Y), the distance between these points is 6.4; Calculate the coordinates of Xn. I came up with that equation using the formula for distance between two points $\displaystyle d=\sqrt{(X2-X1)^2+(Y2-Y1)^2}$

6. Originally Posted by crapmathematician
The situation is: There are two points in a coordinate axis X1(10;11) and Xn(X;Y), the distance between these points is 6.4; Calculate the coordinates of Xn. I came up with that equation using the formula for distance between two points $\displaystyle d=\sqrt{(X2-X1)^2+(Y2-Y1)^2}$
You can't determine one specific point but you'll get a set of points which are placed on a circle around $\displaystyle X_1$ with radius 6.4.

The equation of the circle is:

$\displaystyle (x-10)^2+(y-11)^2=\frac{1024}{25}$

7. Originally Posted by crapmathematician
The situation is: There are two points in a coordinate axis X1(10;11) and Xn(X;Y), the distance between these points is 6.4; Calculate the coordinates of Xn. I came up with that equation using the formula for distance between two points $\displaystyle d=\sqrt{(X2-X1)^2+(Y2-Y1)^2}$
Hi crapmathematician,

The locus of points (X, Y) which are at a given distance from a fixed point (10, 11) is a circle with center at (10, 11) and radius $\displaystyle 6.4$

The equation is $\displaystyle (x-10)^2+(y-11)^2=6.4^2$. There is an infinite number of values for (x, y) that will satisfy this equation.

Never mind! Earboth, you da man!