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Math Help - Stuck while solving equation!

  1. #1
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    Stuck while solving equation!

    I was solving an equation and got to a point where I have no clue what to do next!  40.96=x^2-20x+y^2-22y+221 As you can see I have to find x and y, looks simple, but damn I forgot how to solve it! If anyone could help I would appreciate it a lot!
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  2. #2
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    Quote Originally Posted by crapmathematician View Post
    I was solving an equation and got to a point where I have no clue what to do next!  40.96=x^2-20x+y^2-22y+221 As you can see I have to find x and y, looks simple, but damn I forgot how to solve it! If anyone could help I would appreciate it a lot!
    you have two unknowns in one equation. You need another equation


    bjh
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  3. #3
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    Quote Originally Posted by crapmathematician View Post
    I was solving an equation and got to a point where I have no clue what to do next!  40.96=x^2-20x+y^2-22y+221 As you can see I have to find x and y, looks simple, but damn I forgot how to solve it! If anyone could help I would appreciate it a lot!
    Could you post the whole question? There could be more information that would help you find the answer.
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  4. #4
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    Quote Originally Posted by bjhopper View Post
    you have two unknowns in one equation. You need another equation


    bjh
    Could you be more precise?
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  5. #5
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    Quote Originally Posted by mathemagister View Post
    Could you post the whole question? There could be more information that would help you find the answer.
    The situation is: There are two points in a coordinate axis X1(10;11) and Xn(X;Y), the distance between these points is 6.4; Calculate the coordinates of Xn. I came up with that equation using the formula for distance between two points  d=\sqrt{(X2-X1)^2+(Y2-Y1)^2}
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  6. #6
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    Quote Originally Posted by crapmathematician View Post
    The situation is: There are two points in a coordinate axis X1(10;11) and Xn(X;Y), the distance between these points is 6.4; Calculate the coordinates of Xn. I came up with that equation using the formula for distance between two points  d=\sqrt{(X2-X1)^2+(Y2-Y1)^2}
    You can't determine one specific point but you'll get a set of points which are placed on a circle around X_1 with radius 6.4.

    The equation of the circle is:

    (x-10)^2+(y-11)^2=\frac{1024}{25}
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  7. #7
    A riddle wrapped in an enigma
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    Quote Originally Posted by crapmathematician View Post
    The situation is: There are two points in a coordinate axis X1(10;11) and Xn(X;Y), the distance between these points is 6.4; Calculate the coordinates of Xn. I came up with that equation using the formula for distance between two points  d=\sqrt{(X2-X1)^2+(Y2-Y1)^2}
    Hi crapmathematician,

    The locus of points (X, Y) which are at a given distance from a fixed point (10, 11) is a circle with center at (10, 11) and radius 6.4

    The equation is (x-10)^2+(y-11)^2=6.4^2. There is an infinite number of values for (x, y) that will satisfy this equation.

    Never mind! Earboth, you da man!
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