The perimeter of a soccer field is 340m. the length exceeds the width by 50m find the length and the width... well I got.. 2L + 2W = 340 L = 50W but I keep getting the wrong answer. any help would be appreciated..
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Originally Posted by onymousillusion The perimeter of a soccer field is 340m. the length exceeds the width by 50m find the length and the width... well I got.. 2L + 2W = 340 L = 50W but I keep getting the wrong answer. any help would be appreciated.. Hi onymousillusion, write the length as W+50 Perimeter=2(W+50)+2W=340 Solve for W.
Thanks for the help..
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