# [SOLVED] Graphing a parabola, finding focus/directrix/vertex

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• March 4th 2010, 03:12 PM
zany
[SOLVED] Graphing a parabola, finding focus/directrix/vertex
Well I've completed pretty much every other problem so far except this one, it stumps me. I believe I must complete the square but I've forgotten how I must go about doing that. I tried it already and nothing worked out and it didn't factor correctly to the answer.

$y=1/4(x^2-2x+5)$

steps please (Rofl)

vertex is supposed to be at (1,1), focus (1,2), directrix y=0
• March 4th 2010, 04:01 PM
zany
Nevermind, figured it out, had to logically think it out but I forgot to isolate the terms on both sides making them (Ax - B)^2 = Cy - D

woopsies