Hi all, thanks for taking time out of your day to have a look at my problems. I'm studying and need some help solving these two problems.
I need to solve for k:
Here are the problems:
1) One root of 6x^2 - 3x +k = 0 is (1 - i√23)/4
2) kx^2 - 3x + 4 = 0 one root is twice the other.
I'm not really sure how to do these problems and am really greatful for your help! Btw, the "√" sign in the first problem is a square root sign (just in case someone got confused).
Thanks!
[QUOTE=OurIslamic;468155]Hi all, thanks for taking time out of your day to have a look at my problems. I'm studying and need some help solving these two problems.
I need to solve for k:
Here are the problems:
1) One root of 6x^2 - 3x +k = 0 is (1 - i√23)/4
is easier to calculate.
[/tex]kx^2- 3x+ 4= k(x- a)(x- 2a) [/tex]2) kx^2 - 3x + 4 = 0 one root is twice the other.
Multiply that out and compare "corresponding coefficients to find both a and k.
I'm not really sure how to do these problems and am really greatful for your help! Btw, the "√" sign in the first problem is a square root sign (just in case someone got confused).
Thanks!