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Math Help - Sequence

  1. #1
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    Sequence

    How would I find the third term in the recursively defined sequence: a[sub 1]=3, a[sub k+1]=a[sub k](a[sub k]-1).
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by mike1 View Post
    How would I find the third term in the recursively defined sequence: a[sub 1]=3, a[sub k+1]=a[sub k](a[sub k]-1).
    let a[sub1] be a_1
    let a[subk] be a_k
    let a[sub k+1] be a_(k+1)

    so the third term will have the formula:
    a_3 = a_(2 + 1) = a_2 * (a_2 - 1) ..........but what is a_2? let's find out

    a_2 = a_1 * (a_1 - 1) = 3*(3-1) = 3*2 = 6

    => a_3 = 6*(6 - 1) = 6*5 = 30
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