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Math Help - system of equation word problem, stuck

  1. #1
    Newbie onymousillusion's Avatar
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    system of equation word problem, stuck

    A regulation racquetball court has a perimeter of 120ft, with a length that is twice the width. find the length and the width of such a court.

    I know the answer is the length = 40 and the width = 20;

    but I can't figure out the equation for it any help will be appreciated.
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  2. #2
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    Since you're solving for two variables, you need two equations.

    For the first, perimiter is twice the length plus twice the width.
    For the second, the problem states that the length is twice the width.

    Isolate length (using the second equation), then plug it in to the first equation to solve for width. Then use the second equation to solve for length.
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  3. #3
    Newbie onymousillusion's Avatar
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    120 = 2L + 2W

    But i'm confused about the second one so is it

    2L(2) = 2W ?
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  4. #4
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    Almost. Just translate it from the word problem ("with a length" L "that is twice the width" = 2W).
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  5. #5
    Newbie onymousillusion's Avatar
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    Thanks for all the help..
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