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About LinkBacksCan any one help to manipulate this equation so that we can get a new equation to calulate the value of N with these different variables ( P,M,Z,S and W)
9.36Log10(N+1) + {Log10(P/2.7)}/{0.4+(1094/(N+1)^5.19)} =Log10W - Z*S + 8.27 -2.32log10M
Thanks
Can any one help to manipulate this equation so that we can get a new equation to calulate the value of N with these different variables ( P,M,Z,S and W)
9.36Log10(N+1) + {Log10(P/2.7)}/{0.4+(1094/(N+1)^5.19)} =Log10W - Z*S + 8.27 -2.32log10M
Thanks
This is ambigious : where should the power (^5.19) be put ? Just on the bottom part of the fraction or on the whole fraction ? And does it really have to be that twisted ? Please make the effort of presenting the question in such a way that it is relatively easy and convenient to best answer the actual question.
I'd like to make you realize how hard what you are asking could be : the variable to isolate (N) is :
- in a log, along with an addition (+1)
- outside a log along with a real power (5.19)
It might even not be possible to make N the subject using algebra only.
Yes this is an ambigious equation, N + 1 has power 5.19 and also it is inside log10 . I think this equation is not easy to solve.
In my opinion it can only be done by recurrsion (putting N terms in one side and putting the values of different variables on the other side and checking for which values is N satisfying the equation.)
Could you please edit your first post then ? And eventually put it in LaTeX.
Hmm, this is not what I would call recursion. However, what I mean is that it may not even be possible to isolate all N terms on one side, you might fall into a situation where trying to move one N term on a side will make the other go on the other side. And algebra is useless in this situation. So either you :In my opinion it can only be done by recurrsion (putting N terms in one side and putting the values of different variables on the other side and checking for which values is N satisfying the equation.)
- try to see what can be done with very, very advanced mathematics (believe me, five variables, you are going to have a lot of fun)
- need to put up with it and try to find a solution (you are gonna have fun too ...)
Here, I put it in LaTeX for you, is that right ?
(my eyes !)
Maybe someone will be courageous enough to give it a shot, I would've helped you but I can't stay anymore now
I am new to the forum world and especially with LaTeX. One of the error in your post is the log 10 is only with( P/2.7) in the left side of the equation not with the denominator.
9.36Log10(N+1) + (Log10(P/2.7))/(0.4+1094/(N+1)^5.19) =Log10W - Z*S + 8.27 -2.32log10M
Thanks Ray
Originally Posted by Bacterius
Could you please edit your first post then ? And eventually put it in LaTeX.
Hmm, this is not what I would call recursion. However, what I mean is that it may not even be possible to isolate all N terms on one side, you might fall into a situation where trying to move one N term on a side will make the other go on the other side. And algebra is useless in this situation. So either you :
- try to see what can be done with very, very advanced mathematics (believe me, five variables, you are going to have a lot of fun)
- need to put up with it and try to find a solution (you are gonna have fun too ...)
Here, I put it in LaTeX for you, is that right ?
(my eyes !)
Maybe someone will be courageous enough to give it a shot, I would've helped you but I can't stay anymore now
But you just told me the power was inside the logarithm ? And like this ?
} + \log_{10}{\left ( \frac{P}{2.7} \right ) } \times \left ( 0.4 + \frac{1094}{(N+1)^{5.19}} \right ) = \log_{10}{(W)} - Z)
(sorry I had to cut the equation in half, image too big)
It *might* be solvable, I would recommend putting everything that doesn't involve N to the right, so that you are left with the big brackets and the log of N + 1. Then take the log of 9.36, replace it with another variable, and combine the logs. Then exponentiate and see how you can work it out (it *might* work, I did not try).
Power is just above (N+1) and this term is in the denominator ( below 1094)........i.e:........1094/((N+1)^5.19)
But you just told me the power was inside the logarithm ? And like this ?
} + \log_{10}{\left ( \frac{P}{2.7} \right ) } \left ( 0.4 + \frac{1094}{(N+1)^{5.19}} \right ) = \log_{10}{(W)} - Z)
(sorry I had to cut the equation in half, image too big)
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