im not to sure how far i should be going to solve the equation, am i supposed to find out what x is. if so this is what i have come up with

Question: 5^x-1=2^3x-1 give answer to 3s.f

Workings

log5 ^ 23x-1=x-1

3x-1log5^2=x-1

log5^2=x-1/3x-1

1.4=x-1/3x-1

1.4(3x-1)=x-1

4.2x-1.4=x-1

3.2x-1.4=-1

3.2x=0.4

x=0.4/3.2

x=0.125

3.s.f= 0.13

i know somewhere i have gone really wrong, but not quite sure where. any tips?