Originally Posted by

**JorCherryhead** i begin with this question

Express, log(x+1) - log(x-6) + 2 log x

as a single logarithm

so far i have come to an answer which is slightly puzzeling but i somehow mixed the expression to become equal to something which could be why i had the wrong answer, i have attempted this again, but im at a stage where im getting stuck, any chance for someone to correct me =]

__workings__

log(x+1/x-6) +logx^2

so now i have to times the two logs together

logx^2(x+1/x-6)

logx^2(x+1) divided by logX^2(x-6)......