Show that the equation $ax^2-(a+b)x+b=0$ has a solution for all values of $a$ and $b$.

I think I have to use the discriminant, but I'm not sure how.

2. yes. You are right.
The discriminant is {(a+b)^2 - 4ab} = ....?

3. Oh, nevermind I got it now.
$\Delta=(a-b)^2$

Since $(a-b)$ is squared, the answer will always be positive, hence the reason why there are solutions for all values of $a$ and $b$?

4. Originally Posted by user_5
Oh, nevermind I got it now.
$\Delta=(a-b)^2$

Since $(a-b)$ is squared, the answer will always be positive, hence the reason why there are solutions for all values of $a$ and $b$?
Yes.