Oh, nevermind I got it now.
$\displaystyle \Delta=(a-b)^2$
Since $\displaystyle (a-b)$ is squared, the answer will always be positive, hence the reason why there are solutions for all values of $\displaystyle a$ and $\displaystyle b$?
Oh, nevermind I got it now.
$\displaystyle \Delta=(a-b)^2$
Since $\displaystyle (a-b)$ is squared, the answer will always be positive, hence the reason why there are solutions for all values of $\displaystyle a$ and $\displaystyle b$?