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Math Help - Quadratic Question

  1. #1
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    Quadratic Question

    How do I go about answering this question?

    Show that the equation ax^2-(a+b)x+b=0 has a solution for all values of a and b.

    I think I have to use the discriminant, but I'm not sure how.
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  2. #2
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    yes. You are right.
    The discriminant is {(a+b)^2 - 4ab} = ....?
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  3. #3
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    Oh, nevermind I got it now.
    \Delta=(a-b)^2

    Since (a-b) is squared, the answer will always be positive, hence the reason why there are solutions for all values of a and b?
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  4. #4
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    Quote Originally Posted by user_5 View Post
    Oh, nevermind I got it now.
    \Delta=(a-b)^2

    Since (a-b) is squared, the answer will always be positive, hence the reason why there are solutions for all values of a and b?
    Yes.
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