Solve for X:
X = 25 ^ (1 + log(base 5) X)
My steps:
Bring the exponent down
log(base 25) X = 1 + log(base 5) X
I am stuck here as I have 2 different bases, log X to base 25 and log X to base 5.
How should I solve this? Thanks.
Solve for X:
X = 25 ^ (1 + log(base 5) X)
My steps:
Bring the exponent down
log(base 25) X = 1 + log(base 5) X
I am stuck here as I have 2 different bases, log X to base 25 and log X to base 5.
How should I solve this? Thanks.
why did you take log(base25)?
take log(base5) of both sides:
log(base5)X = log(base5)25 ^ (1 + log(base 5) X)
call log(base5) just log, and remember we're working in base 5
=> logx = (1 + logx)log25
=> logx = (1 + logx)2 .................log(base5)25 = 2
=> logx = 2 + 2logx
=> logx = -2
=> 5^-2 = x
=> 1/5^2 = x
=> x = 1/25