Hello! I'm confused... I know how to find the equation for two points/lines but I don't know what formula should I use for finding equations for 3 lines. should it be the same and i have to find each line and combine them?
Hello! I'm confused... I know how to find the equation for two points/lines but I don't know what formula should I use for finding equations for 3 lines. should it be the same and i have to find each line and combine them?
Ok! Here is the problem:
I draw a Triangle with a vertices (0,8),(12,-8) and (-12,-8) on a graph.
Q: Find the equations for the three lines passing through the vertices.
i know how to get a equation of slope-intercept by using y=mx + b
but getting eqauation for those 3 lines... how?
Hello Anemori,
I can see how you might be confused about this problem.
It's not really worded in the best way.
Here are your vertices: A(0, 8), B(12, -8), C(-12, -8).
You need to define the equations of the lines AB, BC, and AC.
Can you do that using the point-slope form of the linear equation: $\displaystyle y-y_1=m(x-x_1)$
$\displaystyle y-y_1=m(x-x_1)$ is called the 'point-slope form' of a linear equation.
If you don't know this one, and you haven't been told to use it, then we can use the $\displaystyle y=mx+b$
You'll just have to find the slope and y-intercept of each line.
So, which way do you want to go?