how does: log base 4 of 3 become log base 2 of root 3? Im looking for the step by step please. Thanks in advance
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Originally Posted by 200001 how does: log base 4 of 3 become log base 2 of root 3? Im looking for the step by step please. Thanks in advance Change of base rule: $\displaystyle \log_c{a} = \frac{\log_b{a}}{\log_b{c}}$ Power Rule: $\displaystyle k\, \log_b{a} = \log_b{a^k}$ $\displaystyle \log_4{3} = \frac{\log_2{3}}{\log_2{4}}$ Can you use those two rules to get the answer Spoiler: $\displaystyle \log_2{4} = 2$ $\displaystyle \frac{1}{2} \log_2{3} = \log_2{3^{1/2}} = \log_2{\sqrt{3}}$
Yes, awesome, thanks i was missing my numerator on the half power and couldnt make the link between that and it becoming a power Much appreciated
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