I Have to draw the graph of the following(and show working)

x^2+3x+y^2+y= 3/2

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- Feb 27th 2010, 11:35 PMkate1234Need help to graph an equation
I Have to draw the graph of the following(and show working)

x^2+3x+y^2+y= 3/2 - Feb 28th 2010, 12:35 AMHallsofIvy
Complete the square in both x and y:

x^2+ 3x+ ?= (x+ a)^2

y^2+ y+ ?= (y+b)^2

The two "?"s will be numbers of course and you add the same numbers to the right side of the equation. The result will be something like (x+a)^2+ (y+b)^2= r^2; the graph is a circle with center at (-a, -b) and radius a. - Feb 28th 2010, 12:52 PMkate1234
Thanks so much. It was easy once I had the idea from you