Thread: Three variables in linear equation

Hi,
I was going through this article about equation solving Equation solving - Wikipedia, the free encyclopedia. The equation under the overview section has three varibles and one of the solution sets is given. But in order to solve the equation wouldn't I need a set of equations. Given just this one equation, is it possible to come up with a solution set?

Thanks.

Originally Posted by math934

Hi,
I was going through this article about equation solving Equation solving - Wikipedia, the free encyclopedia. The equation under the overview section has three varibles and one of the solution sets is given. But in order to solve the equation wouldn't I need a set of equations. Given just this one equation, is it possible to come up with a solution set?

Thanks.

Dear math934,

In the article that you have refered the given solution is a paricular solution. There are other solutions as well. For example, x = 40/3, y = 22, z = 4 is another solution. If you are given three equations with three unknows you would get only one solution which satisfies all the three equations. But in this case since only one equation is given there are infinte number of solutions.

Do you have any more questions?

[quote=Sudharaka;465340]Dear math934,

In the article that you have refered the given solution is a paricular solution. There are other solutions as well. For example, x = 40/3, y = 22, z = 4 is another solution. If you are given three equations with three unknows you would get only one solution which satisfies all the three equations. But in this case since only one equation is given there are infinte number of solutions.

Do you have any more questions?[/quote



the article you referenced is actually using matricies to solve the equations. this level of math is higher than algebra. that is why you dont understand it. i first faced these equations in calculus.

ThorAsgard,
That makes sense. I was trying to use algebra to find a solution set and I was going around in circles.

Thanks.