# what am i doing wrong? help?

• Feb 27th 2010, 06:28 PM
benjixbunn
what am i doing wrong? help?
the problem is 2/3 (-1/4) + 1/2

i cant get the right answer which is 1/3. i keep getting 4/12 or 1/12. (Headbang)
• Feb 27th 2010, 06:34 PM
ANDS!
Quote:

Originally Posted by benjixbunn
the problem is 2/3 (-1/4) + 1/2

i cant get the right answer which is 1/3. i keep getting 4/12 or 1/12. (Headbang)

Show us how you keep getting 4/12 or 1/12. Can not correct bad behaviors, if we do not know what you are doing. (Punch) I will say, that one of the answers you "keep getting", is the right answer; it just hasn't been reduced. Both show us both of your methods that lead you to 4/12 or 1/12.
• Feb 27th 2010, 06:35 PM
Moo
Quote:

Originally Posted by benjixbunn
the problem is 2/3 (-1/4) + 1/2

i cant get the right answer which is 1/3. i keep getting 4/12 or 1/12. (Headbang)

4/12=4/(3x4)=1/3 :D

(I agree with ANDS!, better to show what you have been suffering for)
• Feb 27th 2010, 06:43 PM
Prove It
Quote:

Originally Posted by benjixbunn
the problem is 2/3 (-1/4) + 1/2

i cant get the right answer which is 1/3. i keep getting 4/12 or 1/12. (Headbang)

$\displaystyle \frac{2}{3}\left(-\frac{1}{4}\right) + \frac{1}{2}$

$\displaystyle = - \frac{2}{12} + \frac{6}{12}$

$\displaystyle = \frac{4}{12}$

$\displaystyle = \frac{4\cdot 1}{4\cdot 3}$

$\displaystyle = \frac{1}{3}$.
• Feb 27th 2010, 06:58 PM
benjixbunn
reduce
ahhh reduce...gotcha(Nod)