Finding the Solution in a Quadratic Equation?

Greetings,

I'm back again with a few problems I'm stuck on. I'm really not sure where to go with them, or how to solve them. Unfortunately I'm a complete dunce when it comes to math, and only manage to get by with help from tutors and such. But these were a few problems that I didn't have time to ask at the tutor's...

I don't know if it makes any difference, but here are *some* of the instructions that were printed at the top of my paper...

Find the solution for each of the following equations.

1- Put the equation in $\displaystyle Ax^2 + Bx + C = 0$ form

2- Determine the form of the equation

3- Find the solutions

-Set each factor equal to 0 and solve

-Solve using the square root method ( $\displaystyle \sqrt{Ax^2 } = +- \sqrt{C}$)

-Solve by factoring

-Use the Quadratic Equation

Most of the problems are the $\displaystyle Ax^2 + Bx + C = 0$ form, and I know that if there is nothing that adds to B and multiplies to C (or maybe it's the other way around) that I need to use the square root method, which is different for me as before we were just told to write "no solution". This time I guess we have to continue it.

I've got most of the problems solved, but there's still a few I'm struggling with and I'm not sure where to go with them. They're probably easier than I think they are, so I'm probably over-thinking things, but...

1. $\displaystyle x^2 + 9x = 0$

For this, do I just bring the 0 over and than add the 0 back in at the end as well, and than solve, or is it something different?

Though I guess bringing over the 0 doesn't make much sense, now that I think about it...

2. $\displaystyle 3x^2 = 60$

I'm really not sure where to go with this one, as it has no Bx and such...

3. $\displaystyle (3x-4)^2 = 16$

4. $\displaystyle 4x^2 - 16 = 0$

Also, for a couple problems I finished I'm just not sure if I got the correct answer. Would anyone be willing to just look them over for me and tell me whether I got them right or wrong?

A.

Problem: $\displaystyle 4x^2 = 2x + 7$

Answer: $\displaystyle \frac {1 + \sqrt{29 }}{2}$ or $\displaystyle \frac {1 - \sqrt{29 }}{2}$

B.

Problem: $\displaystyle x^2 -2x - 10 = 0$

Answer: $\displaystyle \frac {1 + \sqrt{11 }}{1}$ or $\displaystyle \frac {1 - \sqrt{11 }}{1}$

Any help or advice would be very much appreciated. Thank you! :)