I need some help with these.
Solve the following
cos-1(x) = 60° 23' 45"
sin-1 (x) = 60° 23' 45"
tan-1 (x) = 60° 23' 45"
Your calculator should have a cos/sin/tan^-1 function. If not you can use google.
Remember, there are sixty seconds in a minute and sixty minutes in a degree, so when entering it into your calculator, you want to do ((23)(60) + 45)/(3600) Find that decimal, put it after the sixty and find the inverse cos/sin/tan from there.
Hi Wildman,
I hope you intended these to be 3 separate exercises.
You are taking the inverse cos, inverse sin, and inverse tan of some ratio to arrive at $\displaystyle 60^{\circ}23'45"$
Convert: $\displaystyle 60^{\circ}23'45"\Longrightarrow 60+\frac{23}{60}+\frac{45}{3600}=\left(\frac{2899} {48}\right)^{\circ}$
Now just take the Cos, Sin, and Tan of that amount to find the value of x in each case.
[1] $\displaystyle \cos\left(\frac{2899}{48}\right)^{\circ}\approx .4940$
[2] $\displaystyle \sin\left(\frac{2899}{48}\right)^{\circ}\approx .8695$
[3] $\displaystyle \tan\left(\frac{2899}{48}\right)^{\circ}\approx 1.7600$