Can anyone solve this quadratic equation

y = 2x² - 6

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- Feb 27th 2010, 12:19 PMWildmanQuadratic equation
Can anyone solve this quadratic equation

y = 2x² - 6 - Feb 27th 2010, 12:31 PMGusbob
Can't really 'solve' this, but I think you meant

2x² - 6 = 0

2(x² - 3) = 0

x² = 3

x = $\displaystyle \pm \sqrt 3 $

If you really wanted to solve y = 2x² - 6

2x² - (6+y) = 0

2x² = 6 + y

x² = 0.5 (6+ y)

x = $\displaystyle \pm \sqrt {\frac{1}{2} (6+y)} $