solve following equations...

2ln3x=8

9.5e^.005x=19

10^x^2=10^3x-2

6^x+1=4^2x-1

lnx=3lnx=4

log3 (1-x)=1

log(x+1) + log(x-1)=log3

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- February 27th 2010, 12:39 AMPeyton SawyerCollege Algebra
solve following equations...

2ln3x=8

9.5e^.005x=19

10^x^2=10^3x-2

6^x+1=4^2x-1

lnx=3lnx=4

log3 (1-x)=1

log(x+1) + log(x-1)=log3 - February 27th 2010, 12:48 AMProve It
1. Please do not post any more than 2 questions per thread. For the purposes of reading the answers given, the thread can become congested and difficult to keep track of. If you have more than 2 questions, create new threads for them (making sure not to post any more than 2 per thread). You are also more likely to get answers in a more timely manner.

2. Please show some effort. What have you tried? Exactly where are you getting stuck? - February 27th 2010, 12:53 AMPeyton Sawyer
- February 27th 2010, 01:46 AMGrandad
Hello Peyton SawyerHere are some hints. See if you can continue.

Quote:

2ln3x=8

Quote:

9.5e^.005x=19

Quote:

10^x^2=10^3x-2

Quote:

6^x+1=4^2x-1

(where the log is to any base you like)

Quote:

lnx=3lnx=4

Quote:

log3 (1-x)=1

?If so:

Quote:

log(x+1) + log(x-1)=log3

Grandad