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Math Help - College Algebra help: Logarithms

  1. #1
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    Exclamation College Algebra help: Logarithms

    Write as a single logarithm with no numerical coefficients.

    2log 3x-logx + 1/2 log y





    Write as an expanded logarithm with no exponents.

    ln5 (25x^3/y^4)


    *note* the "5" after the "ln" is low so its opposite to a carot or root. I just couldnt type it.
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  2. #2
    Super Member 11rdc11's Avatar
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    Quote Originally Posted by Peyton Sawyer View Post
    Write as a single logarithm with no numerical coefficients.

    2log 3x-logx + 1/2 log y





    Write as an expanded logarithm with no exponents.

    ln5 (25x^3/y^4)


    *note* the "5" after the "ln" is low so its opposite to a carot or root. I just couldnt type it.
    2\log{3x} - \log{x} +\frac{1}{2}\log{y} = \log{(3x)}^2 - \log{x} + \log{\sqrt{y}} = \log{\frac{9x^2\sqrt{y}}{x}}
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  3. #3
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    Quote Originally Posted by 11rdc11 View Post
    2\log{3x} - \log{x} +\frac{1}{2}\log{y} = \log{(3x)}^2 - \log{x} + \log{\sqrt{y}} = \log{\frac{9x^2\sqrt{y}}{x}}
    Thanks! is that answer final as to a single logarithm?
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  4. #4
    Super Member 11rdc11's Avatar
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    \ln_5 \frac{25x^3}{y^4}

    \ln_5{25x^3} - \ln_5{y^4}

    \ln_5{25} +\ln_5{x^3} -4\ln_5{y}

    2 +3\ln_5{x} -4\ln_5{y}
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