Hi what is (3x + 1/x)^2 ???????
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Originally Posted by wolfhound Hi what is (3x + 1/x)^2 ??????? HINT: (a + b)^2 = (a + b) times (a + b)
Originally Posted by Wilmer HINT: (a + b)^2 = (a + b) times (a + b) I know that
Hi! In addition to Wilmer's post One should lnow the binimial theorems In the example it is a = 3x and b = 1/x Can you solve it now? Edit Originally Posted by wolfhound I know that Okay, here is the solution (3x)^2+2*(3x)*(1/x)+(1/x)^2
I know all that pascals triangle stuff ,what I dont understand is what becomes of 3x when its multiplied by 1/x?? or 1/x x 1/x?
Okay, here is the solution (3x)^2+2*(3x)*(1/x)+(1/x)^2 [/QUOTE] thanks
Originally Posted by wolfhound I know all that pascals triangle stuff ,what I dont understand is what becomes of 3x when its multiplied by 1/x?? or 1/x x 1/x?
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