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Math Help - root of the equation

  1. #1
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    root of the equation

    (p^2)(x^2)-12x+p+7=0 has the root 3/2..find the value of p.

    please help,show step by step the answer that u get..thanks
    Last edited by mastermin346; February 26th 2010 at 01:16 AM. Reason: wrong write
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  2. #2
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    Quote Originally Posted by mastermin346 View Post
    (p^2)(x^2)-12x+p+7=0 has the root 3/2..find the value of p.

    please help,show step by step the answer that u get..thanks
    Replace x with 3/2. The result will be a quadratic equation for p. Solve that equation.
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  3. #3
    Super Member Bacterius's Avatar
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    To explain HallsOfIvy's solution, remember that the roots of an equation are the values of x when y = 0. Here, you are given an equation in the form y = f(x) with y = 0 and f(x) = (p^2)(x^2)-12x+p+7 for some p. Since you are given that one root is \frac{3}{2}, you know that when y = 0 (which is our case), x = \frac{3}{2}. So you can just substitute x = \frac{3}{2} into f(x) and solve for p, to find which values of p (there may be more than one) satisfy the equation f(x) = 0 when x = \frac{3}{2}.
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