(p^2)(x^2)-12x+p+7=0 has the root 3/2..find the value of p.

please help,show step by step the answer that u get..thanks

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- Feb 26th 2010, 12:38 AMmastermin346root of the equation
(p^2)(x^2)-12x+p+7=0 has the root 3/2..find the value of p.

please help,show step by step the answer that u get..thanks - Feb 26th 2010, 02:49 AMHallsofIvy
- Feb 26th 2010, 02:58 AMBacterius
To explain HallsOfIvy's solution, remember that the roots of an equation are the values of when . Here, you are given an equation in the form with and for some . Since you are given that one root is , you know that when (which is our case), . So you can just substitute into and solve for , to find which value

__s__of (there may be more than one) satisfy the equation when . :)