I missed class and I am totally lost with these problems. What we have to do is find all real zeros of the function algebraically. My teacher had this equation up on the board but I can;t find it anywhere so any help will help
-bsqaurerooe+-4acdivided by 2a
f(x)=x^2-16
f(x)=t^2-4t^2+4t
g(t)=t^5-6t^3+9t
I think you mean the "quadratic formula" which is
"if , then " (you forgot the ).
As Prove It said, you can factor. If you want to use the quadratic formula, a= 1, b= 0, c= -16. It is always better to factor if you can. Save the quadratic formula for problems where you can't factor.f(x)=x^2-16
This is probably NOT what you intend. This is which has roots t= 0 and t= 4/3. But I suspect you meant which has the root t= 2.f(x)=t^2-4t^2+4t
Again, you could use the quadratic formula with a= 1, b= -4, c= 4.
You can factor this by taking out a single t, which has t= 0 as a root. Now let and the other factor becomes . That has the single root x= 3 so and theng(t)=t^5-6t^3+9t