1. ## Doman interval notation

Express the domain interval notaton.

$H(x) = \frac {t}{\sqrt (t^2-t-6)}$

What I did is factor $t^2-t-6$

$(t-3)(t+2)$

then using interval notation.

(t-3)(t+2) ≤0

t-3 ≤ t-2 ???

am i doing right thing?

2. Originally Posted by Anemori
Express the domain interval notaton.

$H(x) = \frac {t}{\sqrt (t^2-t-6)}$

What I did is factor $t^2-t-6$

$(t-3)(t+2)$

then using interval notation.

(t-3)(t+2) ≤0

t-3 ≤ t-2 ???

am i doing right thing?
$H(t)$ is defined for values of t such that $t^2-t-6 > 0$

$(t-3)(t+2) > 0$

now think about where the graph of $t^2 - t - 6$ is positive ...

domain ... $(-\infty,-2) \cup (3, \infty)$